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10x^2+14x+10=6x^2
We move all terms to the left:
10x^2+14x+10-(6x^2)=0
determiningTheFunctionDomain 10x^2-6x^2+14x+10=0
We add all the numbers together, and all the variables
4x^2+14x+10=0
a = 4; b = 14; c = +10;
Δ = b2-4ac
Δ = 142-4·4·10
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-6}{2*4}=\frac{-20}{8} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+6}{2*4}=\frac{-8}{8} =-1 $
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